Question

A closely wound, circular coil with radius 2.80 cm has 790 turns. Part A What must the current in the coil be if the magnetic field at the center of the coil is 0.0760 T

Answer 1

`I=11.1A`

Step-by-step explanation:

From the question we are told that:

Radius
`R=2.80`

Turns
`N=790`

Magnetic field B=0.0760

Generally the equation for Magnetic field at the center of the coil is mathematically given by

`B=(\mu NI)/(2r)`

`0.076=(4\p*10^-^7*790*I)/(2*0.028)`

`I=(0.076*2*0.028)/(4\p*10^(-7)*790)`

`I=11.1A`