Question

How many moles would be in 85.OmL of 0.750M KOH?

Answer 1

Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

Step-by-step explanation:

Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity = 0.750 M

It is known that molarity is the number of moles of solute present in liter of a solution.

Therefore, moles present in given solution are calculated as follows.

`Molarity = (moles)/(Volume (in L))\\0.750 M = (moles)/(0.085 L)\\moles = 0.0637 mol`

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.