Question

14+5x= 3(-x+3)-11
Find x

Answer 1

x=-2

Explanation:

`14+5x=3\left(-x+3\right)-11`

`3\left(-x+3\right)-11` ← ( Expand)

`14+5x=-3x-2`

`14+5x-14=-3x-2-14` ← ( Subtract 14 from both sides)

`5x=-3x-16`

`5x+3x=-3x-16+3x`

`8x=-16`

`\cfrac{8x}{8}=\cfrac{-16}{8}` ← ( Divide both sides by 8)

`x=-2`

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Answer 2

• -2

Explanation:

In the question we have given with an equation that is 14 + 5x = 3 ( -x + 3 ) - 11 .

And we are asked to find the value of x.

Solution : -

`\longmapsto \: 14 + 5x = 3( - x + 3) - 11`

Step 1 : Solving parenthesis on right side :

`\longmapsto \: 14 + 5x = - 3x + 9 - 11`

On further calculations we get :

`\longmapsto \: 14 + 5x = - 3x - 2`

Step 2 :

Subtracting 14 from both sides :

`\longmapsto \: \cancel{14} - \cancel{14 }+ 5x = -3x -2 - 14`

On further calculations we get :

`\longmapsto \: 5x = - 3x - 16`

Step 3 : Adding 3x on both sides :

`\longmapsto \: 5x + 3x = - \cancel{ 3x} + \cancel{3x} - 16`

On further calculations we get :

`\longmapsto \: 8x = - 16`

Step 4 : Dividing by 8 on both sides :

`\longmapsto \: \frac{ \cancel{8}x}{ \cancel{8}} = \cancel {( - 16)/(8) }`

We get :

`\longmapsto \: \red{\boxed{ \mathfrak{x = - 2}}}`

• Therefore , value of x is -2 .

Verifying :

We're verifying our answer by substituting value of x in given equation . So ,

• 14 + 5x = 3 ( -x + 3 ) - 11

• 14 + 5 ( - 2 ) = 3 { -( -2 ) + 3 ) - 11

• 14 - 10 = 3 ( 2 + 3 ) - 11

• 4 = 3 ( 5 ) - 11

• 4 = 15 - 11

• 4 = 4

• L.H.S = R.H.S

• Hence , Verified .

Therefore , our value for x is valid .

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