The volume of the solid created when the figure is rotated around the line is 13.09 cubic centimeter, rounded to the nearest hundredth.
When you rotate a two-dimensional figure around a line to create a three-dimensional solid, the volume of the solid depends on the shape of the original figure and the axis of rotation. From the description, it appears that the figure is a triangle, and if we rotate a right triangle around one of its legs, we create a cone.
The volume V of a cone is given by the formula:
![\[ V = (1)/(3) \pi r^2 h \]](https://img.qammunity.org/2022/formulas/mathematics/high-school/65p0eir6yfy00q1bov9bjrhnhvj8majg6j.png)
where r is the radius of the base of the cone, and h is the height of the cone.
Assuming that the triangle is rotated around the leg that is 2 cm long, which then becomes the height h of the cone, and the leg that is 5 cm long becomes the slant height (not used directly in the volume formula), the leg opposite the right angle would be the diameter of the cone's base. Therefore, the radius r would be half of that length, or 2.5 cm.
Using these values, we can calculate the volume of the cone:
![\[ r = 2.5 \text{ cm} \]\[ h = 2 \text{ cm} \]](https://img.qammunity.org/2022/formulas/mathematics/high-school/24njndxm2ren692b9kf4fc8948177xtdhb.png)
![\[ V = (1)/(3) \pi (2.5)^2 * 2 \]](https://img.qammunity.org/2022/formulas/mathematics/high-school/ptyxowp0wshfoap0ezd3081a1r7ghdgvwq.png)
V=13.09 cubic centimeter