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What is the pH of a 2.58 x 10^-6 M solution of an acid?
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What is the pH of a 2.58 x 10^-6 M solution of an acid?

User Richard Slater
by
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1 Answer

2 votes

Answer:

5.59

Step-by-step explanation:

The pH of a solution can be found by using the formula


pH = - log [ {H}^(+) ]

From the question we have


ph = - log(2.58 * {10}^( - 6) ) \\ = 5.58838

We have the final answer as

5.59

Hope this helps you

User Serefbilge
by
4.0k points
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