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HELP PLEASE!!!!!!!

140 grams of lead (II) nitrate are dissolved in water then mixed with a solution containing 75 grams of sodium chloride. The reaction creates the precipitate, lead (II) Chloride, and a solution of sodium nitrate. How many grams of lead (II) Chloride can be produced given the initial amount of lead (II) nitrate?

User Potatoe
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1 Answer

3 votes

Answer:

Try a grams calculator, Its pretty to nd one :D

Step-by-step explanation:

User Kjell Gunnar
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