Question

-ww.A

m = 15.0 kg
The block at Position A is released from the spring with 100 J of elastic potential energy. How
much kinetic energy does the block have at Position B? Explain how you know.

Answer 1

v = 3.65 m / s

Step-by-step explanation:

In this exercise we use the conservation of mechanical energy

starting point. Point A compressed spring

Em₀ = 100 J

final point. Point B uncompressed spring

Em_f = K = ½ m v²

energy is conserved

Em₀ = Em₀_f

100 = ½ m v²

v =
`\sqrt{ (2 \ 100 )/(m) }`

v =
`\sqrt {200/15}`

v = 3.65 m / s