Answer:
Option C.
Explanation:
We start with the expression:

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)
We want to find the equivalent expression to this one.
Here, we can do the next two simplifications:

And:

If we apply these two to our initial expression, we can rewrite it as:


Here we can use the second simplification again, to rewrite:

So, concluding, we have:

Then the correct option is C.