Question

Find the equation of the line that

is perpendicular to y = -2x + 1
and contains the point (8, 2).
[?]
y =
x+ [

Answer 1

y=
`(1)/(2)x-2`

Explanation:

Perpendicular lines have negative reciprocal gradients(slopes) so the slope of your new line would be 1/2. Then you use the point to find the new y-intercept

y=mx+b

2=
`(1)/(2)`(8)+b

2=4+b

B=-2

y=
`(1)/(2)x-2`