Answer:
the distance between the submarine and the ocean floor is 11,250 m
Step-by-step explanation:
Given;
speed of the wave, v = 1500 m/s
time of motion of the wave, t = 15 s
The time taken to receive the echo is calculated as;
![time \ of \ motion \ (t) = (total \ distance )/(speed \ of \ wave) = (2d)/(v) \\\\2d = vt\\\\d = (vt)/(2) \\\\d = (1500 * 15)/(2) \\\\d = 11,250 \ m](https://img.qammunity.org/2022/formulas/physics/college/kfxt2wulx7ks8r197zieq3wiict8jzu478.png)
Therefore, the distance between the submarine and the ocean floor is 11,250 m