Question

Which ratio below would work for finding the angle measure of ⦣C?

Question 19 options:

Sin C= 12/15


Sin C= 9/12


Tan C= 9/12


Cos C= 9/15

Answer 1

`\huge\boxed{\tan C=(9)/(12)}`

Explanation:

`sine=(opposite)/(hypotenuse)`

We have:

`opposite=9\\hypotenuse=15`

Substitute:

`\sin C=(9)/(15)`

`cosine=(adjacent)/(hypotenuse)`

We have:

`adjacent=12\\hypotenuse=15`

Substitute:

`\cos C=(12)/(15)`

`tangent=(opposite)/(adjacent)`

We have:

`opposite=9\\adjacent=12`

Substitute:

`\tan C=(9)/(12)`