Answer:
1700 W
Step-by-step explanation:
The heat transfer rate P = kA(T - T')/d where k = thermal conductivity of wall = 1.7 W/m-K, A = area of wall = 0.5 m × 1.2 m = 0.6 m², T = temperature of inner surface = 1400 K, T = temperature of outer surface = 1150 K and d = thickness of wall = 0.15 m
So, P = kA(T - T')/d
substituting the values of the variables into the equation, we have
P = 1.7 W/m-K × 0.6 m²(1400 K - 1150 K)/0.15 m
P = 1.7 W/m-K × 0.6 m² × 250 K/0.15 m
P = 255 Wm/0.15 m
P = 1700 W
So, the heat transfer rate through the wall is 1700 W