Question

ACELLUS PHYSICS HELP!!

A 6.93*10-4 C charge has a potential energy U = -3.09 J at a point in space. What is the electric potential V at that point? Include the sign, + or - . (Unit = V)​

Answer 1

Potential difference, V = -0.000224 Volts

Step-by-step explanation:

Given the following data;

Quantity of charge = 6.93*10-4 C

Energy = -3.09 J

To find the electric potential V at that point?

Mathematically, the energy transferred per unit of charge is given by the formula;

E = QV

Where:

E is the energy

Q is the quantity of charge

V is the potential difference.

Substituting into the formula, we have;

`-3.09 = 6.93*10^(-4) * V`

`V = \frac {6.93*10^(-4)}{-3.09}`

Potential difference, V = -0.000224 Volts