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1 vote
Log base4 (x+3)(x-3)=2
pls I need it urgently​

User Geraldss
by
7.8k points

1 Answer

5 votes

Answer:

x = 5 or -5

Explanation:

if a = b, c^a = c^b

make each side the exponent of 4

4^[log base4 (x+3)(x-3)] = 4^2

since a^(log basea b) = b, (think of the definition of logs as the inverse of exponents here)

(x+3)((x-3) = 16

x^2 -9 = 16x^2 = 25

x = 5 or -5

User Jrudolph
by
8.7k points

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