Question

Find the distance between the points (5, 6) and (5, - 4).

Answer 1

Explanation:

using formula

x1=5 , x2=5 , y1=6 , y2=-4

distance =
`\sqrt{(x2-x1)^(2)+(y2-y1)^(2) }`

=
`\sqrt{(5-5)^(2)+(4-6^(2) }`

=
`\sqrt{(0)^(2)+(-2)^(2) }`

=
`√(0+4)`

=
`√(4)`

=2 units

Answer 2

10 units

Explanation:

(5, 6) and (5, - 4)

To find the distance between two points, we use the distance formula:

`d = \sqrt{(x_(2)-x_1)^2 + (y_2-y_1)^2 }`

Let's plug in what we know.

`d = √((5-5)^2 + (-4-6)^2 )`

Evaluate the parentheses.

`d = √((0)^2 + (-10)^2 )`

Evaluate the exponents.

`d = √((0) + (100) )`

Add.

`d=√(100)`

Evaluate the radical.

d = ±10

Since distance cannot be negative, you answer is 10 units.

Hope this helps!