Question

If Sn=2^n-1

what's the expression of
Sn-1?​

Answer 1

`S(n-1)=2^(n-2)`

Explanation:

Given that,

The value of
`S_n=2^(n-1)`

We need to find an expression for
`S(n-1)`. To find it, put the value of n as (n-1). So,

`S_(n-1)=2^(n-1-1)\\\\=2^(n-2)`

Hence, the value of S(n-1) is equal to
`2^(n-2)`.