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Let H(x) = 5 x 2 - 10 x. Find x such that (x, - 5 ) is on the graph of H(x).

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Answer:

x = 1

Explanation:

The equation in vertex form is ...

H(x) = 5(x^2 -2x) = 5(x^2 -2x +1) -5

H(x) = 5(x -1)^2 -5

The only value of x that will make H(x) = -5, is x=1.

Let H(x) = 5 x 2 - 10 x. Find x such that (x, - 5 ) is on the graph of H(x).-example-1
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