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Sin0=20/29 find tan 0

Sin0=20/29 find tan 0-example-1
User Ness Tyagi
by
3.9k points

2 Answers

0 votes

Answer:

D. tanθ = 20/21

Explanation:

Remember that sinθ = opposite/hypotenuse. In this case, since sinθ = 20/29, we are going to say that opposite = 20 and hypotenuse = 29.

To solve for the adjacent side, use the Pythagorean theorem, a^2 + b^2 = c^2.

When you plug in your values and solve for the other leg, you'll get 21.

Now that we know that the adjacent side/other leg is equal to 21, we can find tanθ, since it's equal to opposite/adjacent.

Opposite = 20

Adjacent = 21

tanθ = 20/21

User Glaxer
by
4.0k points
6 votes

Answer:

Explanation:

here opposite =20, hypotenuse=29

to find adjacent use formula

a^2+b^2=c^2

20^2+b^2=29^2

400+b^2=841

b^2=841-400

b=
√(441\\)

b=21

tan theta=opposite/adjacent

=20/21

therefore tan theta =20/21

User Noah Goodrich
by
4.0k points