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A .100 kg bullet is flying at 200 m/s. How much energy is the bullet storing due to its motion?

1 Answer

3 votes

KE = 2000 J

Step-by-step explanation:

KE = (1/2)mv^2

= (1/2)(0.100 kg)(200 m/s)^2

= 2000 J

User Mayank Garg
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