Answer:
18.0g of glucose are needed
Step-by-step explanation:
Molarity, M, is an unit of concentration widely used in chemistry. Is defined as the ratio between moles of solute (In this case, glucose) and liters of solution (50mL = 0.050L).
To solve this question we must find the moles of glucose that we need to prepare the solution. Then, using the molar mass of glucose (180.156g/mol) we can find the mass that we need:
Moles Glucose:
0.050L * (2.0mol / L) = 0.100 moles Glucose
Mass glucose:
0.100moles Glucose * (180.156g / mol) = 18.0g of glucose are needed