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3 votes
HELP DUE IN 10 MINS!

Which equation has the following: Center (0, -3) and radius: square root of 11.


A. x2 + (y - 3)2 = 11


B. x2 + (y - 3)2 = 121


C. x2 + (y + 3)2 = 11


D. x2 + (y + 3)2 = 121




User Kctang
by
6.9k points

2 Answers

4 votes

Answer:


\text{C. }x^2+(y+3)^2=11

Explanation:

The equation of a circle with radius
r and center
(h, k) is given by:


(x-h)^2+(y-k)^2=r^2.

What we're given:

  • radius of
    √(11)
  • center at
    (0,-3)

Substituting given values, we get:


(x-0)^2+(y-(-3))^2=√(11)^2,\\\boxed{\text{C. }x^2+(y+3)^2=11}

User Manisha  Bano
by
6.3k points
6 votes
D. I believe bc part of the equation is (y-y one) and y one is -3 and two negatives make a positive. And 11 squared it 121
User Mcepl
by
6.0k points
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