Question

An ideal step-down transformer has a turns ratio of 1/106. An ac voltage of amplitude 170 V is applied to the primary. If the primary current amplitude is 8.10 mA, what is the secondary current amplitude

Answer 1

`I_2=0.8586A`

Step-by-step explanation:

From the question we are told that:

Turns Ratio i.e
`(N_2)/(N_1)=(1)/(106) (step down)`

Voltage
`v=170v`

Primary current amplitude
`I_1= 8.10 mA =>8.10*10^(-3)A`

Generally the equation for a Transformer is mathematically given by

`(E_1)/(E_2)=(I_2)/(I_1)=(N_1)/(N_2)`

Therefore

`I_2=(N_1)/(N_2)*I_1`

`I_2=106*8.10*10^(-3)`

`I_2=0.8586A`