Answer:
1.2 × 10²⁴ atoms C
General Formulas and Concepts:
Chemistry
Atomic Structure
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
Step 1: Define
Identify variables
[Given] 24 g C
[Solve] atoms C
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of C: 12.01 g/mol
Step 3: Convert
- [DA] Set up:

- [DA] Divide\Multiply [Cancel out units]:

Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
1.2034 × 10²⁴ atoms C ≈ 1.2 × 10²⁴ atoms C