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Calculate the force of kinetic friction on a 12.3 kg mass if its coefficient of kinetic friction is 0.137

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Answer:

Step-by-step explanation:

All we need here is the equation for frictional force, which is

f = μ
F_n where
F_n=mg That's normal force which is the same thing as weight.

Therefore,


F_n=(12.3)(9.8) to 2 sig figs so


F_n=120 and

f = (.137)(12) to 2 sig figs as well so

f = 16N

User Shahid Malik
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