Question

What is the molarity when 25.0 g of the compound NaClO3 is placed in 85.0 mL of solution?

Answer 1

Answer: Molarity when 25.0 g of the compound
`NaClO_(3)`is placed in 85.0 mL of solution is 294.12 M.

Step-by-step explanation:

Given: Mass = 25.0 g

Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity is the number of moles of a substance divided by volume in liter.

Hence, molarity of given solution is calculated as follows.

`Molarity = (mass)/(Volume (in L))`

Substitute the values into above formula as follows.

`Molarity = (mass)/(volume (in L))\\= (25.0 g)/(0.085 L)\\= 294.12 M`

Thus, we can conclude that molarity when 25.0 g of the compound
`NaClO_(3)`is placed in 85.0 mL of solution is 294.12 M.