Question

X^2-64=0 solve for all real values of x

Answer 1

Hi there! Use the difference of two squares formula to solve the problem below:

`\large \boxed{ {x}^(2) - {y}^(2) = (x + y)(x - y)}`

From the equation, 64 comes from 8². Thus,

`\large{ {x}^(2) - 64 = 0} \\ \large{(x + 8)(x - 8) = 0}`

The question also asks you to solve for all real values. Thus,

`\large{x = 8, - 8}`

Answer

• x = 8,-8 are the real solutions to x²-64 = 0.