Answer:
13 g CO₂
General Formulas and Concepts:
Chemistry
Atomic Structure
- Reading a Periodic Table
- Moles
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Stoichiometry
- Using Dimensional Analysis
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
Step 1: Define
Identify variables
[Given] 6.7 L O₂
[Solve] g O₂
Step 2: Identify Conversions
[STP] 22.4 L = 1 mol
[PT] Molar Mass of O: 16.00 g/mol
[PT] Molar Mass of C: 12.01 g/mol
Molar Mass of CO₂: 12.01 + 2(16.00) = 44.01 g/mol
Step 3: Convert
- [DA] Set up:

- [DA] Divide/Multiply [Cancel out units]:

Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
13.1637 g CO₂ ≈ 13 g CO₂