Question

Two ice skaters suddenly push off against one another starting from a stationary position. The 50 kg skater acquires a speed of 0.3 m/s relative to the ice. What speed does the 60 kg skater acquire relative to the ice

Answer 1

`V_(22)=0.25m/s`

Step-by-step explanation:

From the question we are told that:

Mass 1
`M_1=50kg`

Speed 1
`V_1=0.3m/s`

Mass 2
`M_2=60kg`

Generally the equation for momentum is mathematically given by

`M_1V_(11)+m_2V_(21)=M_1V_(12)+m_2V_(22)`

Where

`v_(11)=v_(21)=0`

Therefore

`M_1V_12-M_2V_22`

`V_(22)=(m_1v22)/(m_2)`

`V_(22)=(m_1V_22)/(m2)`

`V_(22)=(50*0.3)/(60)`

`V_(22)=0.25m/s`