Question

Fish are hung on a spring scale to determine their mass (most fishermen feel no obligation to truthfully report the mass). What is the force constant of the spring in such a scale if it the spring stretches 8.50 cm for a 8.1 kg load

Answer 1

k = 933.88 N/m

Step-by-step explanation:

Given that,

The mass of a load, m = 8.1 kg

The displacement in the spring, x = 8.5 cm

We need to find the force constant of the spring. We know that Hooke's law is given by :

F = -kx

Also,

F = mg (Force due to its weight)

So,

`k=(mg)/(x)\\\\k=(8.1* 9.8)/(0.085)\\\\k=933.88\ N/m`

So, the force constant of the spring is equal to 933.88 N/m.