Answer:
x = -3, y = -3
Explanation:
Solve the following system:
{-y + 2 x = -3 | (equation 1)
3 y + 4 x = -21 | (equation 2)
Swap equation 1 with equation 2:
{4 x + 3 y = -21 | (equation 1)
2 x - y = -3 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x + 3 y = -21 | (equation 1)
0 x - (5 y)/2 = 15/2 | (equation 2)
Multiply equation 2 by 2/5:
{4 x + 3 y = -21 | (equation 1)
0 x - y = 3 | (equation 2)
Multiply equation 2 by -1:
{4 x + 3 y = -21 | (equation 1)
0 x+y = -3 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = -12 | (equation 1)
0 x+y = -3 | (equation 2)
Divide equation 1 by 4:
{x+0 y = -3 | (equation 1)
0 x+y = -3 | (equation 2)
Collect results:
Answer: x = -3, y = -3