Question

Please anyone help me

Answer 1

Answer: The answer is x=
`(-3-√(65) )/(4)`,
`(-3+√(65) )/(4)`

Explanation:

1) You can solve a situation like
`ax^2+bx+c=0` using the quadratic formula

`x=-b`±
`√(b^2-4ac)` / 2a

2) Apply that to the problem and we get x= -3±
`√(3^2-4*2*(-7))`/2*2

3) Solve what's inside the square root and what's at the denominator --> x=-3±
`√(65)`/4

4) separate the solutions --->
`x=(-3+√(65))/(4) , (-3-√(65))/(4)`

5) Your final solutions are
`x=(-3+√(65))/(4) , (-3-√(65))/(4)`