221k views
2 votes
TanA+TanB=TanA+TanB÷1-TanA×TanB if A=30 andB=60​

User Fest
by
7.9k points

1 Answer

6 votes

Answer:


\tan (30 + 60) = unde f ined

Explanation:

Given


\tan (A + B) = (\tan A + \tan B)/(1 - \tan A * \tan B) ---- right expression


A = 30^o; B = 60^o

Required

Solve


\tan (A + B) = (\tan A + \tan B)/(1 - \tan A * \tan B)

Substitute:
A = 30^o; B = 60^o


\tan (30 + 60) = (\tan 30 + \tan 60)/(1 - \tan 30 * \tan 60)

In radical forms, we have:


\tan (30 + 60) = (\sqrt 3/3 + \sqrt 3)/(1 - \sqrt 3/3 * \sqrt 3)


\tan (30 + 60) = (\sqrt 3/3 + \sqrt 3)/(1 - 1)


\tan (30 + 60) = (\sqrt 3/3 + \sqrt 3)/(0)


\tan (30 + 60) = unde f ined

User COYG
by
9.0k points

Related questions

1 answer
5 votes
187k views
asked Jul 11, 2019 55.8k views
DorianFM asked Jul 11, 2019
by DorianFM
7.5k points
1 answer
4 votes
55.8k views
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories