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Find the limit of the function algebraically lim (x^2 -36 / x+6 ) x ->6

User Kobake
by
5.3k points

2 Answers

2 votes

Answer:

A. -1/12

Explanation:

This is the correct answer.

User Henrique Bruno
by
5.2k points
2 votes

9514 1404 393

Answer:

0

Explanation:

The function is defined everywhere except at x=-6. The limit value is the function value at that point.

f(6) = (6^2 -36)/(6 +6) = 0/12 = 0

The limit of the function is 0 as x → 6.

User RajGan
by
4.6k points