Answer:
ab=ab+a
We need to check the following:
(ab)c=a(bc) or not
LHS
(ab)c=(ab+a)c
=(ab+a)c+(ab+a)
=abc+ac+ab+a
RHS
a(bc)=a(bc+b)
=a(bc+b)+a
=abc+ab+a
as LHS ≠ RHS, the operation is not associative
Explanation:
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