Question

A metal gas cylinder is heated from 181 K to 296 K. If the original pressure was 256 psi, what is the pressure after heating also in psi?

Answer 1

419 psi

Step-by-step explanation:

Assuming the gas behaves ideally, we can solve this problem by using Gay-Lussac's law, which states:

• P₁T₂=P₂T₁

Where subscript 1 stands for the initial conditions and 2 for the final ones, meaning that in this case:

• P₁ = 256 psi

• T₂ = 296 K

• P₂ = ?

• T₁ = 181 K

We input the data:

• 256 psi * 296 K = P₂ * 181 K

And solve for P₂:

• P₂ = 419 psi