Question

Propane is used as a fuel for camp stoves. It undergoes combustion to form carbon dioxide and water.

C3H3 +502 – 3 CO2 + 4H20
Determine the number of molecules of propane needed to produce 10.01 liters of carbon dioxide

Answer 1

`8.97x10^(22)molecules C_3H_8`

Step-by-step explanation:

Hello there!

In this case, according to the given chemical reaction and the fact that 22.4 L of a gas are occupied by 1 mol at standard pressure and temperature conditions, it will be possible for us to calculate the number of molecules of propane, by using the Avogadro's number, the 1:3 mole ratio with carbon dioxide and the aforementioned volume-mole ratio to obtain:

`10.01LCO_2*(1molCO_2)/(22.4LCO_2)*(1molC_3H_8 )/(3molCO_2) *(6.022x10^(23)molec\ C_3H_8)/(1molC_3H_8) \\\\=8.97x10^(22)molecules C_3H_8`

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