Answer:
Both parents are heterozygous for the traits and exhibit the dominant phenotype → AaBb
Step-by-step explanation:
Available data:
- widow's peak (A) is dominant over a continuous hairline (a)
- short fingers (B) are dominant over long fingers (b)
- Cross: Two individuals with widow's peak and short fingers
- F1) a child with continuous hairline and long fingers
Genotypes Phenotypes
- AA and Aa individuals with widow's peak
- aa individuals with no widow's peak
- BB and Bb shorted-fingered individuals
- bb longed-fingered individuals
Cross:
Parentals) A-B- x A-B-
Note: the - symbol represents either a dominant or recessive allele.
F1) child with continuous hairline and long fingers → aabb
Each parent provided one allele for each trait to the child. So the child inherited one recessive allele a and one recessive allele b from EACH parent. The fact that both parents could provide one recessive allele to the child for each character, indicates that both parents are heterozygous for the trait. It is the only way of having a child who expresses the double recessive trait.
- Parentals genotypes → AaBb x AaBb
- Child → aabb