Question

I just need help with this pls

Answer 1

Option D

Explanation:

Hello!

Recall the quadratic equation:
`x = (-b\pm√(b^2 - 4ac))/(2a)`

Remember that a quadratic equation is written in the form
`ax^2 + bx + c\\`

So:

• a = 2
• b = 5
• c = -1

Plug the values in and solve:

`x = (-b\pm√(b^2 - 4ac))/(2a)\\\\x = (-5\pm√(5^2 - 4(2)(-1)))/(2(2))$\\\\x = $(-5\pm√(25 +8))/(2(2))$\\\\x = $(-5\pm√(33))/(4)`

This would be
`\boxed{\text{Option D}}`