Answer:
83.33% of the roof area will be occupied by the PV cells
Step-by-step explanation:
Given the data in the question;
time-averaged lighting requirement = 10 W/m²
the annual average solar irradiance = 150 W/m²
the PV efficiency η = 10% = 0.1
battery charging/discharging efficiency η = 80% = 0.8
we know that; Annual average power to the light = × A
Now, the electrical power delivered by the solar cell battery system will be;
⇒ × A × η × η
A = × A × η × η
Such that;
A = A / × A × η × η
A / A = / × η × η
so we substitute
A / A = 10 W/m² / [ 150 W/m² × 0.1 × 0.8 ]
A / A = 10 W/m² / 12 W/m²
A / A = 0.8333
A / A = (0.8333 × 100)%
A / A = 83.33%
Therefore, 83.33% of the roof area will be occupied by the PV cells.
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