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For the given configuration, determine how many different licence plates are possible of (a) digits and letters can be repeated, and (b) digits and letters cannot be repeated. NO LINKS!!



For the given configuration, determine how many different licence plates are possible-example-1
User Dpren
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1 Answer

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9514 1404 393

Answer:

5a,b = 17,576,000; 11,232,000

6. 45,697,600; 32,292,000

7. 6,760,000; 3,276,000

8. 118,813,760; 78,936,000

Explanation:

The number of possible ways the characters can occur is the product of the numbers of ways a character can be selected in each position. If letters or digits cannot repeat, the number of possible selections is reduced by 1 in each new location.

5a. 26×26×26×10×10×10 = 26³×10³ = 17,576,000

5b. 26×25×24×10×9×8 = 11,232,000

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6a. 10²×26⁴ = 45,697,600

6b. 10×9×26×25×24×23 = 32,292,000

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7a. 10⁴×26² = 6,760,000

7b. 10×9×8×7×26×25 = 3,276,000

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8a. 26⁵×10 = 118,813,760

8b. 26×25×24×23×22×10 = 78,936,000

User Hontoni
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