Question

Please HELPPPP me !!!!!

Answer 1

`y = 4x - 3\\Slope \ m_1 = 4`

EQUATION OF LINE PERPENDICULAR

`Lines \ are \ perpendicular => m_1 \cdot m_2 = -1\\`

`slope, m_2 = (-1)/(4)`

`equation \ of \ the\ line \ passing \ through \ (-2, 2) \ slope ,m_2 :\\(y - y_2) =m_2(x - x_2)\\ (y - 2) = (-1)/(4) (x -(-2))\\\\y - 2 = (-1)/(4) (x +2)\\\\y = (-1)/(4)x - (1)/(2) + 2\\\\y = (-1)/(4)x + (3)/(2)`

EQUATION OF LINE PARALLEL

`Lines \ are \ parallel => m_1 \cdot m_3 = 1\\slope, m_3 = (1)/(4)`
`Equation \ of \ the \ line \ through \ (-2, 2) \ and \ slope, m_3:\\(y - y_3) =m_3(x - x_3)\\\\(y-2) = (1)/(4) (x - (-2))\\\\y-2 = (1)/(4)(x+2)\\\\y = (1)/(4)x + (1)/(2) +2\\\\y = (1)/(4)x + (5)/(2)`