Question

A cylinder of gas with a pressure of 8.0 atm is heated from 300. K to 600. K. What will the new pressure of the gas be?

Answer 1

`P_2=16atm`

Step-by-step explanation:

Hello there!

In this case, according to the given information, we can infer we need to use the Gay-Lussac's equation it order to understand this pressure-temperature relationship as shown below:

`(P_1)/(V_1)=(P_2)/(V_2)`

Thus, we solve for P2 and plug in P1, T1 and T2, to obtain:

`P_2=(P_1T_2)/(T_1)\\\\P_2=(8atm*600K)/(300K)\\\\P_2=16atm`

Regards!