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3 votes
Three different sets of objects contain 4, 5, and 12 objects, respectively. How

many unique combinations can be formed by picking one object from each
set?
A. 21
B. 240
C. 60
D. 48

User Magomogo
by
6.7k points

1 Answer

2 votes

Answer:


\text{B. }240}

Explanation:


\binom{4}{1}\cdot\binom{5}{1}\cdot \binom{12}{1}=\boxed{\text{B. }240}}

(Multiplying each of the numbers also yields 240)

User Chuma
by
6.5k points
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