Question

DOES ANYONE KNOW THE ANSWERS TO THESE PROBLEM, PLZ HELP!

Answer 1

Q.1.

Sum of angles of a triangle = 180°

∠A + ∠B + ∠c = 180

(3x - 9) + (4x + 15) + 90 = 180

3x - 9 + 4x + 15 + 90 = 180

7x + 96 = 180

7x = 84

x = 12

∠A = 3x - 9 = 3(12) - 9 = 36 - 9 = 27°

∠B = 4x + 15 = 4(12) + 15 = 48 + 15 = 63°

∠A = 27°

∠B = 63°

Q.2.

`using \ pythagoras \ theorem \\x^2 = 7^2 + (7√(3) )^(2) = 49 + 49(3) = 196\\x = √(196) = 14`

`sin y = (opposite)/(hypotenuse) = (7√(3) )/(14) = (√(3) )/(2) \\\\y = sin^(-1) ((√(3) )/(2) ) = 60`

x = 14

y = 60°