Question

Identify the initial conditions y(0) and y'(0) for the vertical motion of an object, if the object is thrown downward at a velocity of 6 m/s from a height of 30m. (take the origin to be on the ground)

Answer 1

The right solution is "y(0) = 30 m" and "y'(0) = -6 m/s²".

Explanation:

Given,

Velocity,

u = -6 m/s

Height,

h = 30 m

Now,

By using shifting of origin, we get

⇒
`(y-30)=-6t+(1)/(2)(-9.8)t^2`

`y-30=-6t-4.9t^2`

`y=30-6t-4.9t^2`

hence,

The value of y(0) is:

y(0) =
`30-0-0`

=
`30 \ m`

The value of y'(0) is:

y'(t) =
`-6-9.8t`

y'(0) =
`-6 \ m/s^2`