Answer:
b. 485 kPa
Step-by-step explanation:
Gay-Lussac's law express that the pressure of a gas under constant volume is directly proportional to the absolute temperature. The equation is:
P1T2 = P2T1
P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas
Where P1 = 74psi
T2 = 20°C + 273.15 = 293.15K
P2 = ?
T1 = (95°F -32) * 5/9 + 273.15 = 308.15K
Replacing:
74psi*293.15K = P2*308.15K
70.4psi
In kPa:
70.4psi * (6.895kPa / 1psi) =
b. 485 kPa