Question

HELP!!!!!!!!!

A toy car has a motor capable of moving the car at 10m/s up a 35 degree ramp. If the motor exerts a force of 500N to the car, what is the power rating of the motor in kW?

Answer 1

4.096 kW

Step-by-step explanation:

Applying,

P = Fvcos∅................. Equation 1

Where P = Power of the motor, F = Force exerted on the motor, v = Velocity, ∅ = angle.

From the question,

Given: F = 500 N, v = 10 m/s, ∅ = 35°

Substitute these values into equation 1

P = 500×10×cos35°

P = 4095.8 W

P = 4.096 kW

Hence the power rating of the moto in kW is 4.096 kW