Question

Can anybody help meh :(

A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing through the cross-sectional area in 10s is

Answer 1

`n=1.56* 10^(17)` electrons

Step-by-step explanation:

Given that,

Total charge = 9 mC = 0.009 C

0.009 C of charge passes through a wire in 3.6 s.

Let q' is the charge that passes through it in 10 s.

So,

`(0.009 )/(3.6)=(q')/(10)\\\\q'=(0.009 * 10)/(3.6)\\\\q'=0.025\ C`

We know that,

q = ne

Where

n is the number of electrons

So,

`n=(q)/(e)\\\\n=(0.025)/(1.6* 10^(-19))\\\\n=1.56* 10^(17)`

So,
`1.56* 10^(17)`electrons must pass through the cross-sectional area.