12M HNO3
Step-by-step explanation:
A 600-ml solution of 16M nitric acid contains
16M HNO3 × 0.6 L = 9.6 m HNO3
so by increasing the volume by 200 ml the molarity of the solution becomes
Molarity = (9.6 mol HNO3)/(0.800 L)
= 12M HNO3
6.5m questions
8.6m answers