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If I add 200 mL of water to 600 mL of 16 M HNO3 what will the solution's final molarity be?

User Abbe
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1 Answer

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12M HNO3

Step-by-step explanation:

A 600-ml solution of 16M nitric acid contains

16M HNO3 × 0.6 L = 9.6 m HNO3

so by increasing the volume by 200 ml the molarity of the solution becomes

Molarity = (9.6 mol HNO3)/(0.800 L)

= 12M HNO3

User Mantis
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