Question

Fermi energy of conduction electrons in silver is 0.548 J. Calculate the number of such electrons in unit cm3

Answer 1

`n=1.86*10^(-30)m^3`

Step-by-step explanation:

From the question we are told that:

Fermi energy of conduction electrons
`E_f=0.548J`

Generally the equation for Fermi energy is mathematically given by

`E_f=(3)/(\pi)^2/3*(h^2)/(8m)*{n^(2/3)}`

`E_f=(3)/(\pi)^2/3*(h^2)/(8m)*{n^(2/3)}`

`{n^(2/3)}=(E_f)/((3)/(\pi)^2/3*(h^2)/(8m))`

Where

h= Planck's constant

`{n^(2/3)}=(E_f)/((3)/(\pi)^2/3*(h^2)/(8m))`

`{n^(2/3)}=(0.548J)/(3.62*10^(-19))`

`n=(1.51*10^(-20))^(3/2)`

`n=1.86*10^(-30)m^3`